Signal Processing - Study Mode
[#341] The filter used for pulse shaping is
Correct Answer
(D) All of the above
[#342] For a function g(t), it is given that $$intlimits_{ - infty }^{ + infty } {gleft( t
ight){e^{ - jomega t}}dt = omega {e^{ - 2{omega ^2}}}} $$ xa0 xa0 for any real value $$omega .$$ xa0If $$yleft( t
ight) = intlimits_{ - infty }^t {gleft( au
ight)d au ,} $$ xa0 xa0then $$intlimits_{ - infty }^{ + infty } {yleft( t
ight)dt} $$ xa0 is . . . . . . . .
Correct Answer
(B) $$ - j$$
[#343] An LTI system has a wide-sense stationary (WSS) input signal with zero mean, Its output is
Correct Answer
(B) zero mean and WSS signal
[#344] The Dirac delta function δ(t) is defined as
Correct Answer
(D) [delta left( t
ight) = left{ x08egin{array}{l}
infty ,,,,t = 0\
0,,,,{
m{otherwise}}
end{array}
ight.{
m{ and }}intlimits_{ - infty }^infty {delta left( t
ight)dt = 1} ]
[#345] A signals m(t) with bandwidth 500 Hz is first multiplied by a signal g(t) where $$gleft( t
ight) = sumlimits_{k = - infty }^infty {{{left( { - 1}
ight)}^k}delta left( {t - 0.5 imes {{10}^{ - 4}}k}
ight)} $$ The resulting signal is then passed through an ideal low pass filter with bandwidth 1 kHz. The output of the low pass filter would be
Correct Answer
(C) 0