Signal Processing - Study Mode

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[#336] The impulse response of a linear time invariant system is h(n) = {1, [underline 2 ], 1, -1}. The response for the input signal x(n) = {[underline 1 ], 2, 3, 1} is

(A) {1, 8, 4, 8, 3, -1, -2}

(B) {1, 4, 8, 3, 8, -2, -2}

(C) {1, 4, 8, 8, 3, -2, -1}

(D) {1, 8, 3, 8, 8, 4, -1}

Correct Answer

(C) {1, 4, 8, 8, 3, -2, -1}

[#337] With the following equations, the time invariant systems are $$eqalign{
& 1.,frac{{{d^2}yleft( t
ight)}}{{d{t^2}}} + 2tfrac{d}{{dt}}yleft( t
ight) + 5yleft( t
ight) = xleft( t
ight) cr
& 2.,yleft( t
ight) = {e^{ - 2xleft( t
ight)}} cr
& 3.,yleft( t
ight) = left[ {frac{d}{{dt}}xleft( t
ight)}
ight] cr
& 4.,yleft( t
ight) = frac{d}{{dt}}left[ {{e^{ - 2t}}xleft( t
ight)}
ight] cr} $$

(A) 1 and 2

(B) 1 and 4

(C) 2 and 3

(D) 3 and 4

Correct Answer

(C) 2 and 3

[#338] Two ideal quantizers A and B have following specifications: A: 5 bit Quantizer with input dynamic range of -1V to +1V with Q 1 as quantization noise power B: 8 bit Quantizer with input dynamic range of -0.5V to +0.5V with Q 2 as quantization noise power. Then $$frac{{{{ ext{Q}}_1}}}{{{{ ext{Q}}_2}}}$$ will be

(A) 16

(B) 256

(C) 64

(D) 128

Correct Answer

(B) 256

[#339] Laplace transform of 1 - e -at is given by

(A) $$frac{1}{{s + a}}$$

(B) $$frac{s}{{s + a}}$$

(C) $$frac{a}{{s + a}}$$

(D) $$frac{a}{{aleft( {s + a} ight)}}$$

Correct Answer

(D) $$frac{a}{{aleft( {s + a} ight)}}$$

[#340] The dead band range of a first order IIR filter given by y(n) = 0.5y (n - 1) + x(n) on quantization operation due to rounding with a step size of is:

(A) $$frac{1}{4}$$

(B) $$frac{1}{{16}}$$

(C) $$frac{1}{8}$$

(D) $$frac{1}{{32}}$$

Correct Answer

(D) $$frac{1}{{32}}$$