Profit And Loss - Study Mode
[#306] The profit earned by selling a article at Rs. 5520 is equal to the loss incurred on selling the same article at Rs. 4080. What will be percent profit, if the article is sold at Rs. 6000?
Correct Answer
(C) 25%
Explanation
Solution: $$eqalign{
& { ext{Cost price of article}} cr
& = { ext{Rs}}{ ext{.}}left( {frac{{5520 + 4080}}{2}}
ight) cr
& = { ext{Rs}}{ ext{.}}frac{{9600}}{2} cr
& = { ext{Rs}}{ ext{. 4800}} cr
& { ext{When selling price}} cr
& = { ext{Rs}}{ ext{. 6000 then}} cr
& { ext{Profit}} = { ext{Rs}}{ ext{.}}left( {6000 - 4800}
ight) cr
& ,,,,,,,,,,,,,,,, = { ext{Rs}}{ ext{. 1200}} cr
& herefore { ext{Profit percent}} cr
& = frac{{1200}}{{4800}} imes 100 cr
& = 25\% cr} $$
[#307] A man purchased the articles for Rs. 123684. He sold 60% of those at a profit of 16.66% and rest at a loss. Find the loss percentage on the remaining if the overall loss is 14%?
Correct Answer
(C) 60%
Explanation
Solution: He gets 14% of loss that means he gets 86% of CP. Thus, Let the CP be Rs. 100 60% of 100 + 16.66% of 60% of 100 + 40% of 100 - x% of 40% of 100 = 86% of 100 70 + 40X = 86 40X = 86 - 70 = 16 X = $$frac{{16}}{{40}}$$ X = 0.4 Hence, Loss = 1 - 0.4 = 0.6 = 60%
[#308] A reduction of 20% in the price of sugar enables a housewife to purchase 6 kg more for Rs. 240. What is original price per kg of sugar.
Correct Answer
(A) Rs. 10 per Kg
Explanation
Solution: It is based on inverse proportion or product constancy concept. Reduction in price 20% amount of sugar will increase 25% It means, 25% = 6 Kg. So, Initially, total Sugar = 6 × 4 = 24Kg. Thus, Original price of the sugar was, $$frac{{240}}{{24}}$$ = Rs. 10 per kg. Note: Let initial price of 100 kg Sugar was Rs. 100. Now, 20% decrease in rate then rate of 100 kg sugar would be Rs. 80. So, Rs. 80 = 100 kg sugar. Rs. 1 = $$frac{{100}}{{80}}$$ kg sugar. Rs. 100 = $$frac{{100 imes 100}}{{80}}$$ xa0 = 125 Kg sugar. Increment in sugar = 25 kg. % increment = $$frac{{25 imes 100}}{{100}}$$ xa0 = 25%. Means 20% rate decrease, 25% of consumption increase.
[#309] A dishonest dealer purchases goods at 20% discount of the cost price of Rs. X and also cheats his wholesaler by getting 20% extra through false weighing, per kg. Then he marks up his goods by 80% of x, but he gives a discount of 25% besides he cheats his customer by weighing 10% less than the required. What is his overall profit percentage?
Correct Answer
(A) 125%
Explanation
Solution: Let actual cost price of an article be Rs. 1 (in place of X). Now he purchases goods worth Rs. 120 and pays Rs. 80, since 20% discount is allowed. So, the CP = $$frac{{80}}{{120}} = frac{2}{3}$$
Again, MP, SP = 135 (since 25% discount)
Thus, the trader sells goods worth Rs. 90 instead of 100g and charges Rs. 135. Therefore the effective SP = $$frac{{135}}{{90}} = frac{3}{2}$$
$$eqalign{
& { ext{Profit}},\% cr
& = {frac{{ { {frac{3}{2}} - {frac{2}{3}} } }}{{frac{2}{3}}}} imes 100 cr
& = 125\% cr} $$
[#310] Hotel Aditya has 10 single AC rooms, 5 double AC rooms and 18 non AC rooms. The fixed monthly rent of hotel is 150,000. The per day maintenance cost is Rs. 100 for double AC room, Rs. 75 for single AC room and Rs. 40 for non AC room. The per day charges are Rs. 600 for double AC room, Rs. 400 for single AC room and Rs. 250 for non AC room. In April 2003, the occupancy rate of non AC room was 50%, 70% of single AC room and 40% of double AC rooms. Find the profit/loss % for that particular month.
Correct Answer
(B) 10.33% (loss)
Explanation
Solution: Maintenance, = Rs. (100 × 5 × 30) + (75 × 10 × 30) + (40 × 18 × 30) = 15,000 + 22,500 + 21,600 = Rs. 59,100 Total cost = 2,09,100 Amount Received, = (9 × 250 × 30) + (7 × 400 × 30) + (2 × 600 × 30) = 67,500 + 84,000 + 36,000 = 1, 87, 500 Loss (%), $$eqalign{
& = {frac{{209100 - 187500}}{{209100}}} imes 100 cr
& = {frac{{21600}}{{209100}}} imes 100 cr
& = 10.33\% cr} $$