Profit And Loss - Study Mode
[#286] Srinivas sold an article for Rs. 6800 and incurred a loss. Had he sold the article foe Rs. 7850, his gain would have been equal to half of the amount of loss that he incurred. At what price should he sell the article to have 20% profit = ?
Correct Answer
(B) Rs. 9000
Explanation
Solution: Let the cost price of a article be x Then, loss = (x - 6800) Again, profit = (7850 - x) According to given information we get Now, $$eqalign{
& left( {7850 - x}
ight) = frac{{x - 6800}}{2} cr
& Rightarrow 15700 - 2x = x - 6800 cr
& Rightarrow 2x + x = 15700 + 6800 cr
& Rightarrow 3x = 22500 cr
& herefore x = frac{{22500}}{3} = 7500 cr
& { ext{If profit }}\% = 20\% { ext{ then}} cr
& herefore { ext{SP}} = frac{{7500 imes 120}}{{100}} cr
& ,,,,,,,,,,,,,, = { ext{Rs}}{ ext{.9000}} cr} $$
[#287] By selling an article at $$frac{2}{3}$$ of the marked price, there is a loss of 10% . The profit percent, when the article is sold at the marked price, is -
Correct Answer
(C) 35%
Explanation
Solution: $$eqalign{
& { ext{Let the M}}{ ext{.P be Rs}}{ ext{. }}x. cr
& { ext{Then,}} cr
& { ext{S}}{ ext{.P}}{ ext{.}} = { ext{Rs}}.frac{2}{3}x,{ ext{loss}} = 10\% cr
& { ext{C}}{ ext{.P}}{ ext{.}} = { ext{Rs}}.left( {frac{{100}}{{90}} imes frac{2}{3}x}
ight) cr
& ,,,,,,,,,,,, = { ext{Rs}}.frac{{20}}{{27}}x cr
& { ext{If an article is sold at M}}{ ext{.P}}{ ext{.}} cr
& { ext{Then,}} cr
& { ext{Profit}} = { ext{Rs}}.left( {x - frac{{20}}{{27}}x}
ight) cr
& ,,,,,,,,,,,,,,,, = { ext{Rs}}.frac{{7x}}{{27}} cr
& herefore { ext{Profit}}\% cr
& = left( {frac{{7x}}{{27}} imes frac{{27}}{{20x}} imes 100}
ight)\% cr
& = 35\% cr} $$
[#288] Raghavan purchase a scooter at $$frac{13}{15}$$ of its selling price and sold it at 12% more than its selling price. His gain is -
Correct Answer
(B) $$29frac{3}{{13}}$$%
Explanation
Solution: $$eqalign{
& { ext{Let S}}{ ext{.P}}{ ext{. be Rs}}{ ext{. }}x cr
& { ext{Then,}} cr
& { ext{C}}{ ext{.P}}{ ext{.}} = { ext{Rs}}.frac{{13}}{{15}}x, cr
& { ext{Receipt}} = 112\% { ext{ of Rs}}{ ext{. }}x cr
& ,,,,,,,,,,,,,,,,,,,, = { ext{Rs}}.frac{{28}}{{25}}x cr
& { ext{Gain}} = { ext{Rs}}.left( {frac{{28x}}{{25}} - frac{{13x}}{{15}}}
ight) cr
& ,,,,,,,,,,,,,, = { ext{Rs}}.frac{{19x}}{{75}} cr
& herefore { ext{Gain}}\% cr
& = left( {frac{{19x}}{{75}} imes frac{{15}}{{13x}} imes 100}
ight)\% cr
& = frac{{380}}{{13}}\% cr
& = 29frac{3}{{13}}\% cr} $$
[#289] A sells a bicycle to B at a profit of 20% . B sells it to C at a profit of 25% . If C pays Rs. 225 for it, the cost price of the bicycle for A is = ?
Correct Answer
(D) Rs. 150
Explanation
Solution: According to the question, A B C 10 [xrightarrow{{20\% { ext{ profit}}}}] 12 [xrightarrow{{25\% { ext{ profit}}}}] 12 + 3 = 15 [ o ] 225 $$eqalign{
& herefore { ext{1 unit}} = { ext{15}} cr
& herefore { ext{10 units}} = 10 imes 15 cr
& ,,,,,,,,,,,,,,,,,,,,,,,,,,, = { ext{Rs}}{ ext{.150}} cr} $$
[#290] A house worth Rs. 150000 is sold by X at a 5% profit to Y, Y sells the house back to X at a 2% loss. Then find profit and loss in the entire transaction = ?
Correct Answer
(C) X gains Rs. 3150
Explanation
Solution: Money spent by X = Rs. 150000 Money received by X = 105% of Rs. 150000 = Rs. 157500 C.P. to X = 98% of Rs. 157500 = Rs. 154350 ∴ X gains Rs. (157500 - 154350) = Rs. 3150