Profit And Loss - Study Mode

[#276] The marked price of an article is 10% higher than cost price. A discount of 10% is given on marked price. In this kind of seller bears = ?
Correct Answer

(D) A loss of 1%

Explanation

Solution: Let cost price of the article is = Rs. 100 Marked price is 10% high of cost price mean = Rs. 110 Discount always given on marked price 10% discount of marked price means $$ = frac{{10}}{{100}} imes 110 = { ext{ Rs}}{ ext{. 11}}$$ ∴ Selling price = Marked price - Discount Selling price = 110 - 11 = Rs. 99 $$eqalign{
& herefore { ext{Loss}}\% cr
& = frac{{{ ext{Cost price}} - { ext{Selling price}}}}{{{ ext{Cost price}}}} cr
& Rightarrow { ext{Loss}}\% = frac{{100 - 99}}{{100}} imes 100 cr
& ,,,,,,,,,,,,,,,,,,,,,,,,, = frac{1}{{100}} imes 100 cr
& ,,,,,,,,,,,,,,,,,,,,,,,,, = 1\% cr} $$

[#277] Rajlani sold a machine for Rs. 22000 with a discount of 8% on the labeled price and made a profit of $$22frac{2}{3}$$% . What would have been the profit percent if the machine was sold without discount on the label price?
Correct Answer

(D) $$33frac{1}{3}$$

Explanation

Solution: Marked price of the machine = Rs. 22000 Selling price $$eqalign{
& = { ext{Rs}}{ ext{.}}left( {22000 - frac{{8 imes 22000}}{{100}}}
ight) cr
& = { ext{Rs}}{ ext{. 20240}} cr
& { ext{Profit}} = 22frac{2}{3}\% = frac{{68}}{3}\% cr} $$ Let cost price of the machine be Rs. x $$eqalign{
& Rightarrow x + frac{{68}}{3}\% { ext{ of }}x = { ext{Rs}}{ ext{. }}20240 cr
& Rightarrow x + frac{{68x}}{{300}} = { ext{Rs}}{ ext{. }}20240 cr
& Rightarrow frac{{368x}}{{300}} = { ext{Rs}}{ ext{. }}20240 cr
& Rightarrow x = { ext{Rs}}.left( {frac{{20240 imes 300}}{{368}}}
ight) cr
& Rightarrow x = { ext{Rs}}{ ext{. }}16500 cr} $$ Profit % when machine was sold without discount $$eqalign{
& = frac{{22000 - 16500}}{{16500}} imes 100 cr
& = 33frac{1}{3}\% cr} $$

[#278] A shopkeeper sells rice at 10% profit and uses weight 30% less the actual measure. His gain percent is = ?
Correct Answer

(B) $$57frac{1}{7}\% $$

Explanation

Solution: Let CP of 1 kg. of rice be Rs. 100 As he uses 30% less weight ∴ SP of 700 gm. of rice = Rs. 110 ∴ SP of 100 gm. of rice $$eqalign{
& = frac{{110}}{{700}} imes 1000 cr
& = frac{{1100}}{7} cr
& = 157frac{1}{7} cr
& herefore { ext{Profit}}\% = 57frac{1}{7}\% cr} $$

[#279] A dinner set is quoted for Rs. 1500. A customer pays Rs. 1173 for it. If the customer get a series of two discounts and the rate of first discount is 15% then the rate of second discount was?
Correct Answer

(D) 8%

Explanation

Solution: According to the question, First discount = 15% S.P. of dinner set after first discount = (100 – 15)% of Rs. 1500 $$eqalign{
& = Rs.,left( {frac{{1500 imes 85}}{{100}}}
ight) cr
& = { ext{Rs}}{ ext{.}},1275 cr} $$ Second discount = Rs. ( 1275 – 1173 ) = Rs. 102 If second discount be d %, then $$eqalign{
& herefore frac{{1275 imes { ext{d}}}}{{100}} = 102 cr
& Rightarrow d = frac{{102 imes 100}}{{1275}} cr
& ,,,,,,,,,,,,,, = 8\% cr} $$

[#280] A dishonest dealer defrauds to the extent of x% in buying as well as selling is goods by using faulty weight. What will be the gain percent on his outlay?
Correct Answer

(C) $$left( {2x + frac{{{x^2}}}{{100}}} ight)\% $$

Explanation

Solution: $$eqalign{
& { ext{Total profit}} cr
& = x + x + frac{{x imes x}}{{100}} cr
& = left( {2x + frac{{{x^2}}}{{100}}}
ight)\% cr} $$