Profit And Loss - Study Mode

[#246] x sells two articles for Rs. 4000 each with no loss and no gain in the transaction. If one was sold at a gain of 25% the other is sold at a loss of = ?
Correct Answer

(C) $$16frac{2}{3}$$%

Explanation

Solution: Total SP = Rs. 8000 and Total CP = Rs. 8000 SP of 1 st articles = Rs. 4000 Gain on it = 25% ∴ CP of 1 st articles $$ = { ext{Rs}}{ ext{.}},left( {frac{{100}}{{125}} imes 4000}
ight) = { ext{Rs}}{ ext{.}},3200$$ ∴ CP of 2 nd articles = Rs. (8000 - 3200) = Rs. 4800 SP of 2 nd articles = Rs. 4000 ∴ Loss on 2 nd articles $$eqalign{
& = left( {frac{{800}}{{4800}} imes 100}
ight)\% cr
& = 16frac{2}{3}\% cr} $$

[#247] If I would have purchased 11 articles for Rs. 10 and sold all the articles at the rate of 10 for Rs. 11, the profit percent would have been = ?
Correct Answer

(C) 21%

Explanation

Solution: Cost price of 11 oranges = Rs. 10 Cost price of 1 orange = Rs. $$frac{{10}}{{11}}$$ Selling price of 10 oranges = Rs. 11 Selling price of 1 orange = Rs. $$frac{{11}}{{10}}$$ Since Selling price > Cost price, there is profit Profit per orange = Selling price - Cost price $$eqalign{
& = { ext{Rs}}{ ext{.}},frac{{11}}{{10}} - { ext{Rs}}{ ext{.}},frac{{10}}{{11}} cr
& = { ext{Rs}}{ ext{.}},frac{{121 - 100}}{{110}} cr
& = { ext{Rs}}{ ext{.}},frac{{21}}{{110}} cr} $$ Profit on 11 oranges $$ = frac{{21}}{{110}} imes 11 = { ext{Rs}}{ ext{.}},2.1$$ $$eqalign{
& { ext{Profit}}\% = frac{{{ ext{Profit}}}}{{{ ext{Cost}},{ ext{Price}}}} imes 100\% cr
& ,,,,,,,,,,,,,,,,,,,,, = frac{{2.1}}{{10}} imes 100\% cr
& ,,,,,,,,,,,,,,,,,,,,, = 21\% cr} $$

[#248] A person bought some articles at the rate of 5 per rupee and the same number at the rate of 4 per rupee. He mixed both the types and sold at the rate of 9 for 2 rupees. In this business he suffered a loss of Rs. 3. The total number of articles bought by him was = ?
Correct Answer

(B) 1080

Explanation

Solution: let the person buy 10 articles. Total CP $$ = { ext{Rs}}{ ext{.}},left( {1 + frac{5}{4}}
ight) = { ext{Rs}}{ ext{.}},frac{9}{4}$$ SP of 10 articles $$eqalign{
& = { ext{Rs}}{ ext{.}},frac{2}{9} imes 10 cr
& = { ext{Rs}}{ ext{.}},frac{{20}}{9} cr} $$ so Loss = $$left( {frac{9}{4} - frac{{20}}{9}}
ight) = frac{1}{{36}}$$ Now, if loss is Rs.$$frac{1}{{36}}$$, number of article = 10 So If loss is Rs. 3, number of article = 36 × 10 × 3 = 1080

[#249] In a shop, 80% of the articles are sold at a profit of 10% and the remaining at a loss of 40%. What is the overall profit/loss ?
Correct Answer

(D) No profit no loss

Explanation

Solution: Let the total C.P. of all the articles be Rs. x. Then, C.P. of 80% of the articles = 80% of Rs. x. $$ = { ext{Rs}}.frac{{4x}}{5}$$ C.P. of the remaining articles $$eqalign{
& = { ext{Rs}}.left( {x - frac{{4x}}{5}}
ight) cr
& = { ext{Rs}}.frac{x}{5} cr
& { ext{Total S}}{ ext{.P}}{ ext{.}} cr
& = Rs.left( {110\% { ext{ of }}frac{{4x}}{5} + 60\% { ext{ of }}frac{x}{5}}
ight) cr
& = { ext{Rs}}.left( {frac{{22x}}{{25}} + frac{{3x}}{{25}}}
ight) cr
& = { ext{Rs}}{ ext{. }}x. cr} $$ Since C.P. = S.P. there is no profit no loss

[#250] I purchased 120 exercise books at the rate of Rs. 3 each and sold $$frac{1}{3}$$ of them at the rate of Rs. 4 each, $$frac{1}{2}$$ of them at the rate of Rs. 5 each and the rest at the cost price. My profit percent is -
Correct Answer

(C) $$44frac{4}{9}$$%

Explanation

Solution: Total C.P. = Rs. (120 × 3) = Rs. 360 Total S.P. = Rs. (40 × 4 + 60 × 5 + 20 × 3) = Rs. 520 Profit = Rs. (520 - 360) = Rs. 160 $$eqalign{
& herefore { ext{Profit}}\% cr
& = left( {frac{{160}}{{360}} imes 100}
ight)\% cr
& = left( {frac{{400}}{9}}
ight)\% cr
& = 44frac{4}{9}\% cr} $$