Strength Of Materials In Me - Study Mode
[#391] Within elastic limit, stress is
Correct Answer
(B) Directly proportional to strain
[#392] When a body is subjected to a direct tensile stress $$left( {{sigma _{ ext{x}}}}
ight)$$ xa0in one plane accompanied by a simple shear stress $$left( {{ au _{{ ext{xy}}}}}
ight),$$ xa0the maximum normal stress is
Correct Answer
(A) $$frac{{{sigma _{ ext{x}}}}}{2} + frac{1}{2} imes sqrt {sigma _{ ext{x}}^2 + 4 au _{{ ext{xy}}}^2} $$
[#393] When a body is subjected to a direct tensile stress $$left( {{sigma _{ ext{x}}}}
ight)$$ xa0in one plane accompanied by a simple shear stress $$left( {{ au _{{ ext{xy}}}}}
ight),$$ xa0the minimum normal stress is
Correct Answer
(B) $$frac{{{sigma _{ ext{x}}}}}{2} - frac{1}{2} imes sqrt {sigma _{ ext{x}}^2 + 4 au _{{ ext{xy}}}^2} $$
[#394] When a body is subjected to biaxial stress i.e. direct stresses $$left( {{sigma _{ ext{x}}}}
ight)$$ xa0and $$left( {{sigma _{ ext{y}}}}
ight)$$ xa0in two mutually perpendicular planes accompanied by a simple shear stress $$left( {{ au _{{ ext{xy}}}}}
ight),$$ xa0then maximum normal stress is
Correct Answer
(A) $$frac{{{sigma _{ ext{x}}} + {sigma _{ ext{y}}}}}{2} + frac{1}{2}sqrt {{{left( {{sigma _{ ext{x}}} - {sigma _{ ext{y}}}}
ight)}^2} + 4 au _{{ ext{xy}}}^2} $$
[#395] When a body is subjected to biaxial stress i.e. direct stresses $$left( {{sigma _{ ext{x}}}}
ight)$$ xa0and $$left( {{sigma _{ ext{y}}}}
ight)$$ xa0in two mutually perpendicular planes accompanied by a simple shear stress $$left( {{ au _{{ ext{xy}}}}}
ight),$$ xa0then minimum normal stress is
Correct Answer
(B) $$frac{{{sigma _{ ext{x}}} + {sigma _{ ext{y}}}}}{2} - frac{1}{2}sqrt {{{left( {{sigma _{ ext{x}}} - {sigma _{ ext{y}}}}
ight)}^2} + 4 au _{{ ext{xy}}}^2} $$