Percentage - Study Mode

[#161] Nandini Basu bought an article for Rs. 5844. She gave Rs. 156 to a mechanic to remove its defect. She then sold it for Rs. 5700. What was her loss percent ?
Correct Answer

(A) 5%

Explanation

Solution: Actual cost price of an article : = Rs. (5844 + 156) = Rs. 6000 Selling price of that article = Rs. 5700 Loss = Rs. (6000 - 5700) = Rs. 300 Loss percent : = $$frac{300}{6000}$$ × 100 = 5%

[#162] Rajeev buy goods worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sale tax @ 10%. Find the amount he will have to pay for the goods ?
Correct Answer

(A) Rs. 6876.10

Explanation

Solution: Rebate = 6% of Rs. 6650 $$eqalign{
& = { ext{Rs}}{ ext{. }}left( {frac{6}{{100}} imes 6650}
ight) cr
& = { ext{Rs}}{ ext{. 399}} cr} $$ Sales tax = 10 % of (6650 - 399) $$eqalign{
& = { ext{Rs}}{ ext{. }}left( {frac{{10}}{{100}} imes 6251}
ight) cr
& = { ext{Rs}}{ ext{. 625}}{ ext{.10}} cr} $$ ∴ Final amount = Rs. (6251 + 625.10) = Rs. 6876.10

[#163] In a year, a man manages to sell only 65% of the chicken he owns. How many chicken should the man own to sell 47775 chicken in a years ?
Correct Answer

55000

Explanation

Solution: Let the required number of chicken be x Then, 65% of x = 47775 $$eqalign{
& Rightarrow frac{{65}}{{100}}x = 47775 cr
& Rightarrow x = frac{{47775 imes 100}}{{65}} cr
& Rightarrow x = 73500 cr} $$

[#164] When 125 is subtracted from a number, it reduces to its 37.5 percent. What is 25 percent of that number ?
Correct Answer

(A) 50

Explanation

Solution: Let the number be x Then, $$eqalign{
& Rightarrow x = 125 = 37frac{1}{2}\% { ext{ of }}x cr
& Rightarrow x - 125 = frac{{75}}{2} imes frac{1}{{100}} imes x cr
& Rightarrow x - 125 = frac{{3x}}{8} cr
& Rightarrow x - frac{{3x}}{8} = 125 cr
& Rightarrow frac{{5x}}{8} = 125 cr
& Rightarrow x = left( {frac{{125 imes 8}}{5}}
ight) cr
& Rightarrow x = 200 cr
& herefore 25\% { ext{ of 200}} cr
& = left( {frac{{25}}{{100}} imes 200}
ight) cr
& = 50 cr} $$

[#165] In an examination it is required to get 40% of the aggregate marks to pass. A student get 261 marks and is declared failed by 4% marks. What are the maximum aggregate marks a student can get ?
Correct Answer

700

Explanation

Solution: Let the maximum marks be x. Then, $$eqalign{
& left( {40 - 4}
ight)\% { ext{ of }}x = 261 cr
& Rightarrow 36\% { ext{ of }}x = 261 cr
& Rightarrow frac{{36}}{{100}}x = 261 cr
& Rightarrow x = left( {frac{{261 imes 100}}{{36}}}
ight) cr
& Rightarrow x = 725 cr} $$