C Plus Plus Miscellaneous - Study Mode
[#596] What will be the output of the following C++ code? #include <iostream>
#include <queue>
using namespace std
int main ()
{
priority_queue<int> mypq
mypq.push(30)
mypq.push(100)
mypq.push(25)
mypq.push(40)
while (!mypq.empty())
{
cout << " " << mypq.top()
mypq.pop()
}
cout << endl
return 0
}
Correct Answer
(A) 100 40 30 25
[#597] What will be the output of the following C++ code? #include <iostream>
#include <iterator>
#include <list>
using namespace std
int main ()
{
list<int> firstlist, secondlist
for (int i = 1
i <= 2
i++)
{
firstlist.push_back(i)
secondlist.push_back(i * 10)
}
list<int> :: iterator it
it = firstlist.begin()
advance (it, 3)
copy (secondlist.begin(), secondlist.end(), inserter(firstlist, it))
for ( it = firstlist.begin()
it != firstlist.end()
++it )
cout << *it << " "
return 0
}
Correct Answer
(A) 10 20 1 2
[#598] What will be the output of the following C++ code? #include <iostream>
using namespace std
template<typename type>
type Max(type Var1, type Var2)
{
return Var1 > Var2 ? Var1:Var2
}
int main()
{
int p
p = Max(100, 200)
cout << p << endl
return 0
}
Correct Answer
(B) 200
[#599] What will be the output of the following C++ code? #include <iostream>
#include <exception>
using namespace std
class base { virtual void dummy() {} }
class derived: public base { int a
}
int main ()
{
try
{
base * pba = new derived
base * pbb = new base
derived * pd
pd = dynamic_cast<derived*>(pba)
if (pd == 0)
cout << "Null pointer on first type-cast" << endl
pd = dynamic_cast<derived*>(pbb)
if (pd == 0)
cout << "Null pointer on second type-cast" << endl
}
catch (exception& e)
{
cout << "Exception: " << e.what()
}
return 0
}
Correct Answer
(B) Null pointer on second type-cast
[#600] What will be the output of the following C++ code? #include <iostream>
using namespace std
struct A
{
virtual ~A()
{
cout << "~A()" << endl
}
void operator delete[](void* p, size_t)
{
cout << "A :: operator delete[]" << endl
delete [] p
}
}
struct B : A
{
void operator delete[](void* p, size_t)
{
cout << "B :: operator delete[]" << endl
delete [] p
}
}
int main()
{
A* bp = new B[3]
delete[] bp
}
Correct Answer
(D) Warning