Chain Rule

Name: _____________________

Date: _____________________

Instructions: Answer all questions. Write your answers clearly in the space provided.

Question 1:

If 12 carpenters, working 6 hours a day, can make 460 chairs in 24 days, how many chairs will 18 carpenters make in 36 days, each working 8 hours a day ?

A. 1260
B. 1320
C. 920
D. 1380
Answer: _________
Question 2:

If 5 spiders can catch five files in five minutes, how many files can hundred spiders catch in 100 minutes ?

A. 100
B. 500
C. 1000
D. 2000
Answer: _________
Question 3:

2 persons working 2 hours a day assemble 2 machine in 2 days. The number of machines assemble by 6 persons working 6 hours a day in 6 day is ?

A. 6
B. 18
C. 27
D. 54
Answer: _________
Question 4:

A wall of 100 meters can be built by 7 men or 10 women in 10 days. How many days will 14 men and 20 women take to build a wall of 600 metres ?

A. 15
B. 20
C. 25
D. 30
Answer: _________
Question 5:

21 binders can bind 1400 books in 15 days. How many binders will required to bind 800 books in 20 days ?

A. 7
B. 9
C. 12
D. 14
Answer: _________
Question 6:

20 men complete one-third of a piece of work in 20 days. How many more men should be employed to finish the rest of the work in 25 more days ?

A. 10
B. 12
C. 15
D. 20
Answer: _________
Question 7:

A rope makes 70 rounds of the circumference of a cylinder whose radius of the base is 14 cm. How many times can it go round a cylinder with radius 20 cm ?

A. 40
B. 49
C. 100
D. None of these
Answer: _________
Question 8:

A contract is to be complete in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, $$frac{4}{7}{ ext{ }}$$ of the work is completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day ?

A. 80
B. 81
C. 82
D. 83
Answer: _________
Question 9:

12 persons can do a piece of work in 4 days. How many persons are required to complete 8 times the work in half the time ?

A. 144
B. 180
C. 190
D. 192
Answer: _________
Question 10:

On a certain map of India the actual distance of 1450 km between two cities Delhi and Kolkata is shown as 5 cm. What scale is used to draw the map ?

A. $$1:15 imes {10^6}$$
B. $$1:20 imes {10^6}$$
C. $$1:25 imes {10^6}$$
D. $$1:29 imes {10^6}$$
Answer: _________
Question 11:

A flagstaff 17.5 m high caste a shadow of length 40.25 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be ?

A. 10 m
B. 12.5 m
C. 17.5 m
D. 21.25 m
Answer: _________
Question 12:

A man completes $$frac{5}{8}$$ of a job in 10 days. At this rate, how many more days will it take him to finish the job ?

A. 5
B. 6
C. 7
D. $${ ext{7}}frac{1}{2}$$
Answer: _________
Question 13:

56 men can complete a piece of work in 24 days. In how many days can 42 men complete the same piece of work ?

A. 18
B. 32
C. 48
D. 98
Answer: _________
Question 14:

30 men can do a piece of work in 16 days. How many men would be required to do the same work in 20 days ?

A. 12
B. 24
C. 36
D. 48
Answer: _________
Question 15:

4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat-weavers in 8 days ?

A. 4
B. 8
C. 12
D. 16
Answer: _________
Question 16:

If 7 maids with 7 mops cleaned 7 floors in 7 hours, how long would it take 3 maids to mop 3 floors with 3 mops ?

A. $$frac{7}{3}{ ext{ hours}}$$
B. $${ ext{3 hours}}$$
C. $$frac{{49}}{3}{ ext{ hours}}$$
D. $${ ext{7 hours}}$$
Answer: _________
Question 17:

Four gardeners with four grass mowers mow 400 sq. m of ground in 4 hours. How long would it take for eight gardeners with eight grass mowers to mow 800 sq. m of ground ?

A. 4 hours
B. 6 hours
C. 8 hours
D. 12 hours
Answer: _________
Question 18:

Running at the same constant rate, 6 identical machines can produce a total of 180 bottles per hour. How many bottles could 15 such machines produce on 30 minutes ?

A. 225
B. 250
C. 300
D. 350
Answer: _________
Question 19:

If 6 persons working 8 hours a day earn Rs. 8400 per week, then 9 persons working 6 hours a day will earn per week ?

A. Rs. 8400
B. Rs. 9450
C. Rs. 16200
D. Rs. 16800
Answer: _________
Question 20:

If 5 workers can collect 60 kg wheat in 3 days, how many kilograms of wheat will 8 workers collect in 5 days ?

A. 80 kg
B. 100 kg
C. 120 kg
D. 160 kg
Answer: _________
Question 21:

50 people consume 350 kg of rice in 30 days. In how many days will 35 people consume 50 kg of rice ?

A. 2 days
B. 3 days
C. 5 days
D. 7 days
Answer: _________
Question 22:

Working 8 hours a day, 12 men can do a work in 30 days. Working 4 hours a day, 18 men can do work in ?

A. 30 days
B. 40 days
C. 45 days
D. 50 days
Answer: _________
Question 23:

5 persons can prepare an admission list in 8 days working 7 hours a day. If 2 persons join them so as to complete the work in 4 days, they need to work per day for ?

A. 8 hours
B. 9 hours
C. 10 hours
D. 12 hours
Answer: _________
Question 24:

4 persons can prepare an admission list in 8 days working 7 hours a day. If 3 persons join them so as to complete the work in 4 days, they need to work per day for ?

A. 6 hours
B. 8 hours
C. 10 hours
D. 12 hours
Answer: _________
Question 25:

3 pumps , working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day ?

A. 9
B. 10
C. 11
D. 12
Answer: _________
Question 26:

If 5 men or 7 women can earn Rs. 5250 per day, how much would 7 men and 13 women earn per day ?

A. Rs. 11600
B. Rs. 11700
C. Rs. 16100
D. Rs. 17100
Answer: _________
Question 27:

3 men or 6 women can do a piece of work in 20 days. In how days will 12 men and 8 women do the same work ?

A. $${ ext{3}}frac{1}{2}{ ext{ days}}$$
B. $${ ext{3}}frac{3}{4}{ ext{ days}}$$
C. [{ ext{4 days}}]
D. [{ ext{5 days}}]
Answer: _________
Question 28:

49 pumps can empty a reservoir in $$6frac{1}{2}$$ days, working 8 hours a day. If 196 pumps are used for 5 hours each day, then the same work will be complete in ?

A. 2 days
B. $${ ext{2}}frac{1}{2}$$ days
C. $${ ext{2}}frac{3}{5}$$ days
D. 3 days
Answer: _________
Question 29:

30 labourers working 7 hours a day can finish a piece of work in 18 days. If the labourers work 6 hours a day, then the number of labourers to finish the same piece of work in 30 days, will be ?

A. 15
B. 21
C. 22
D. 25
Answer: _________
Question 30:

3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?

A. 9
B. 10
C. 11
D. 12
Answer: _________
Question 31:

If the cost of x metres of wire is d rupees, then what is the cost of y metres of wire at the same rate?

A. Rs. $$ {frac{{{ ext{xy}}}}{{ ext{d}}}} $$
B. $${ ext{Rs}}{ ext{.}} {xd} $$
C. $${ ext{Rs}}{ ext{.}} {yd} $$
D. Rs. $$ {frac{{{ ext{yd}}}}{{ ext{x}}}} $$
Answer: _________
Question 32:

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

A. 648
B. 1800
C. 2700
D. 10800
Answer: _________
Question 33:

A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is:

A. $$29frac{1}{5}$$
B. $$37frac{1}{4}$$
C. 42
D. 54
Answer: _________
Question 34:

39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?

A. 10
B. 13
C. 14
D. 15
Answer: _________
Question 35:

A man completes $$frac{5}{8}$$ of a job in 10 days. At this rate, how many more days will it takes him to finish the job?

A. 5
B. 6
C. 7
D. $$7frac{1}{2}$$
Answer: _________
Question 36:

If a quarter kg of potato costs 60 paise, how many paise will 200 gm cost?

A. 48 paise
B. 54 paise
C. 56 paise
D. 72 paise
Answer: _________
Question 37:

In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk?

A. 1
B. $$frac{1}{{40}}$$
C. 40
D. 80
Answer: _________
Question 38:

A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions mad by the larger wheel is:

A. 4
B. 9
C. 12
D. 49
Answer: _________
Question 39:

If 7 spiders make 7 webs in 7 days, then 1 spider will make 1 web in how many days?

A. 1
B. [frac{7}{2}]
C. 7
D. 49
Answer: _________
Question 40:

A flagstaff 17.5 m high casts a shadow of length 40.25 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be:

A. 10 m
B. 12.5 m
C. 17.5 m
D. 21.25 m
Answer: _________
Question 41:

In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?

A. 20
B. 30
C. 40
D. 50
Answer: _________
Question 42:

An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metres of cloth?

A. 178
B. 195
C. 204
D. 488
Answer: _________
Question 43:

36 men can complete a piece of work in 18 days. In how many days will 27 men complete the same work?

A. 12
B. 18
C. 22
D. 24
Answer: _________
Question 44:

4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat-weavers in 8 days?

A. 4
B. 8
C. 12
D. 16
Answer: _________
Question 45:

The price of 357 mangoes is Rs. 1517.25. What will be the approximate price of 49 dozens of such mangoes ?

A. Rs. 3000
B. Rs. 3500
C. Rs. 4000
D. Rs. 2500
Answer: _________
Question 46:

An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metres of cloth ?

A. 178
B. 195
C. 24
D. 488
Answer: _________
Question 47:

A snapshot $${ ext{1}}frac{7}{8} imes 2frac{1}{2}$$ xa0 is to be enlarged so that the longer dimension is 4. What will be the dimension of the shorter side ?

A. $${ ext{2}}frac{3}{8}$$
B. $${ ext{2}}frac{1}{2}$$
C. $${ ext{3}}$$
D. $${ ext{3}}frac{3}{8}$$
Answer: _________
Question 48:

A canteen requires 651 bananas for a week. Totally, how many bananas will it require for the months of April, May and June ?

A. 8463
B. 8547
C. 9086
D. 9284
Answer: _________
Question 49:

If $$frac{4}{9}$$ th of a bucket is filled in 1 minute, the rest of it will be filled in ?

A. $${ ext{ 1 minute}}$$
B. $$frac{9}{4}{ ext{ minute}}$$
C. $$frac{5}{4}{ ext{ minute}}$$
D. $$frac{4}{5}{ ext{ minute}}$$
Answer: _________
Question 50:

If 5 engines consume 6 metric tonnes of coal when each is running 9 hours a day, how many metric tonnes of coal will be needed for 8 engines, each running 10 hours a day, it begin given that 3 engines of the former type consume as much as 4 engines of the latter type ?

A. $${ ext{3}}frac{1}{8}$$
B. 8
C. $${ ext{8}}frac{8}{9}$$
D. $${ ext{6}}frac{{12}}{{25}}$$
Answer: _________
Question 51:

If 9 men working $${ ext{7}}frac{1}{2}$$ hours a day can finish a piece of work in 20 days, then how many days will be taken by 12 men, working 6 hours a day to finish the work ? (It is being given that 2 men of latter type work as much as 3 men of the former type.)

A. $${ ext{9}}frac{1}{2}$$
B. 11
C. $${ ext{12}}frac{1}{2}$$
D. 13
Answer: _________
Question 52:

15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take, 3 women do as much work as 2 men ?

A. 18
B. 20
C. 25
D. 30
Answer: _________
Question 53:

In a barrack of soldiers there was stock of food for 190 days for 4000 soldiers. After 30 days 800 soldiers left the barrack. For how many days shall the left over food last for the remaining soldiers ?

A. 175 days
B. 200 days
C. 225 days
D. 250 days
Answer: _________
Question 54:

A garrison of 500 men had provisions for 27 days. After 3 days a reinforcement of 300 men arrived. For how many more days will the remaining food last now ?

A. 15
B. 16
C. $${ ext{17}}frac{1}{2}$$
D. 18
Answer: _________
Question 55:

A garrison had provision for a certain number of days. After 10 days, $$frac{1}{5}$$ of the men desert and it is found that the provisions will now last just as long as before. How long was that ?

A. 15 days
B. 25 days
C. 35 days
D. 50 days
Answer: _________
Question 56:

A fort has provisions for 50 days. If after 10 days they are strengthened by 500 men and the food lasts for 35 days longer, the number of men originally in the fort were ?

A. 2500
B. 3000
C. 3500
D. 4000
Answer: _________
Question 57:

A team of workers was employed by a contractor who undertook to finish 360 pieces of an article in a certain number of days. Making four more pieces per day than was planned, they could complete the job a day ahead of schedule. How many days did they take to complete the job ?

A. 8 days
B. 9 days
C. 10 days
D. 12 days
Answer: _________
Question 58:

The work done by a women in 8 hours is equal to the work done by a man in 6 hours and by a boy in 12 hours. If working 6 hours per day 9 men can complete a work in 6 days, then in how many days can 12 men, 12 women and 12 boys together finish the same work, working 8 hours per day ?

A. $${ ext{1}}frac{1}{2}{ ext{ days}}$$
B. $${ ext{3 days}}$$
C. $${ ext{3}}frac{2}{3}{ ext{ days}}$$
D. $${ ext{4}}frac{1}{2}{ ext{ days}}$$
Answer: _________
Question 59:

12 men and 18 boys, working $$7frac{1}{2}$$ hours a day, can do a piece of work in 60 days. If a man works equal to 2 boys, then how many boys will be required to help 21 men to do twice the work in 50 days, working 9 hours a day ?

A. 30
B. 42
C. 48
D. 90
Answer: _________
Question 60:

If 2 m, 60 cm cloths is required for one shirt, then the cloth required for 7 shirts is ?

A. 14 m 80 cm
B. 18 m 20 cm
C. 15 m 20 cm
D. 16 m 80 cm
Answer: _________
Question 61:

The cost of 4 dozen papers is Rs. 24. The cost of 1 score of papers (in rupees) is ?

A. 40
B. 20
C. 10
D. 42
Answer: _________
Question 62:

The cost of 8 fans and 14 ovens is Rs. 36520. What is the cost of 12 fans and 21 ovens ?

A. Rs. 56800
B. Rs. 54780
C. Rs. 57950
D. Cannot be determined
Answer: _________
Question 63:

The cost of 5 kgs of apples is Rs. 450. The cost of 12 dozen mangoes is Rs. 4320 and the cost of 4 kgs of oranges is Rs. 240. What is the total cost of 8 kg of apples, 8 dozen of mangoes and 8 kg of oranges ?

A. Rs. 4020
B. Rs. 4080
C. Rs. 4050
D. Other than those given as option
Answer: _________
Question 64:

The cost of 21 pencils and 9 clippers is Rs. 819. The cost price of 7 pencils and 3 clippers is = ?

A. Rs. 204
B. Rs. 409
C. Rs. 273
D. Rs. 208
Answer: _________
Question 65:

Large, medium and small ships are used to bring water. 4 large ships carry as much water as 7 small ships, 3 medium ships carry the same amount of water as 2 large ships and 1 small ship. 15 large, 7 medium and 14 small ships, each made 36 journeys and brought a certain quantity of water. In how many journeys would 12 large, 14 medium and 21 small ships bring the same quantity ?

A. 25
B. 29
C. 32
D. 49
Answer: _________
Question 66:

If 17 labourers can dig a ditch 26 m long in 18 days, working 8 hours a day
how many more labourers should be engaged to dig a similar ditch 39 m long in 6 days, each labourer working 9 hours a day ?

A. 34
B. 51
C. 68
D. 85
Answer: _________

Answer Key

1: D
Solution: Let the required number of chairs be x Then, More carpenters, More chairs (Direct proportion) More hours per day, More chairs (Direct proportion) More days, More chairs (Direct proportion) [left. x08egin{gathered}
,,,,{ ext{Carpenters 12}}:18 hfill \
{ ext{Hours per day 6}}:8 hfill \
,,,,,,,,,,,,,,,,,{ ext{Days 24}}:{ ext{36}} hfill \
end{gathered}
ight}::460:x] $$eqalign{
& herefore { ext{ }}12 imes 6 imes 24 imes x = 18 imes 8 imes 36 imes 460 cr
& Leftrightarrow x = frac{{left( {18 imes 8 imes 36 imes 460}
ight)}}{{left( {12 imes 6 imes 24}
ight)}} cr
& Leftrightarrow x = 1380 cr} $$ ∴ Required number of chairs = 1380
2: D
Solution: Let the required number of chairs be x. Then, More spiders, More flies (Direct proportion) More time, More flies (Direct proportion) [left. x08egin{gathered}
,,,{ ext{Spiders 5}}:100 hfill \
{ ext{Minutes 5}}:100 hfill \
end{gathered}
ight}::5:x] $$eqalign{
& herefore { ext{ }}5 imes 5 imes x = 100 imes 100 imes 5 cr
& Leftrightarrow x = frac{{left( {100 imes 100 imes 5}
ight)}}{{left( {5 imes 5}
ight)}} cr
& Leftrightarrow x = 2000 cr} $$
3: D
Solution: Let the required number of machine be x More persons, More machines (Direct proportion) More working working hours, More machines (Direct proportion) More days, More machines (Direct proportion) [left. x08egin{gathered}
,,,,,,,,,,,,,,,,,,,{ ext{Persons 2}}:6 hfill \
,,,, { ext{Working hours 2}}:6 hfill \
,,,,,,,,,,,,,,,,,,,,,,,,,{ ext{Days 2}}:{ ext{6}} hfill \
end{gathered}
ight}::2:x] $$eqalign{
& herefore { ext{ }}2 imes 2 imes 2 imes x = 6 imes 6 imes 6 imes 2 cr
& Leftrightarrow x = frac{{left( {6 imes 6 imes 6 imes 2}
ight)}}{{left( {2 imes 2 imes 2}
ight)}} cr
& Leftrightarrow x = 54 cr} $$
4: A
Solution: Let the required number of days be x 7 men = 10 women (14 men and 20 women) = (20 + 20) women = 40 women More length, More days (Direct proportion) More women, Less days (Indirect proportion) [left. x08egin{gathered}
{ ext{Length 100}}:600 hfill \
,,{ ext{Women 40}}:10 hfill \
end{gathered}
ight}::10:x] $$eqalign{
& herefore { ext{ }}100 imes 40 imes x = 600 imes 10 imes 10 cr
& Leftrightarrow x = frac{{left( {600 imes 10 imes 10}
ight)}}{{left( {100 imes 40}
ight)}} cr
& Leftrightarrow x = 15 cr} $$
5: B
Solution: Let the required number of binders be x Less books, Less binders (Direct proportion) More days, Less binders (Indirect proportion) [left. x08egin{gathered}
{ ext{Books 1400}}:800 hfill \
,,,,,,,,,{ ext{Days 20}}:15 hfill \
end{gathered}
ight}::21:x] $$eqalign{
& herefore { ext{ }}1400 imes 20 imes x = 800 imes 15 imes 21 cr
& Leftrightarrow x = frac{{left( {800 imes 15 imes 21}
ight)}}{{left( {1400 imes 20}
ight)}} cr
& Leftrightarrow x = 9 cr} $$
6: B
Solution: Let the total number of men be x Work done = $$frac{1}{3}$$ Remaining work = $$left( {1 - frac{1}{3}}
ight) = frac{2}{3}$$ More work, More men (Direct proportion) More days, Less men (Indirect proportion) [left. x08egin{gathered}
,{ ext{Work }}frac{1}{3}:frac{2}{3} hfill \
{ ext{Days 25}}:20 hfill \
end{gathered}
ight}::20:x] $$eqalign{
& herefore { ext{ }}left( {frac{1}{3} imes 25 imes x}
ight) = left( {frac{2}{3} imes 20 imes 20}
ight) cr
& Leftrightarrow x = frac{{800}}{{25}} cr
& Leftrightarrow x = 32 cr} $$ ∴ More men to be employed = (32 - 20) = 12
7: B
Solution: Let the required number of rounds be x More radius, Less rounds (Indirect proportion) $$eqalign{
& herefore { ext{ }}20:14::70:x cr
& Leftrightarrow left( {20 imes x}
ight) = left( {14 imes 70}
ight) cr
& Leftrightarrow x = frac{{left( {14 imes 70}
ight)}}{{20}} cr
& Leftrightarrow x = 49 cr} $$
8: B
Solution: Remaining work = $$left( {1 - frac{4}{7}}
ight){ ext{ = }}frac{3}{7}$$ Remaining period = (46 - 33) = 13 days Let the total men working at it be x Less work, Less men (Direct proportion) Less days, More men (Indirect proportion) More hour/day, Less men (Indirect proportion) [left. x08egin{gathered}
,,,,,{ ext{Work }}frac{4}{7}:frac{3}{7} hfill \
,,,,,,,{ ext{Men 13}}:33 hfill \
{ ext{Hour/day }}9:8 hfill \
end{gathered}
ight}::117:x] $$eqalign{
& herefore { ext{ }}frac{4}{7} imes 13 imes 9 imes x = frac{3}{7} imes 33 imes 8 imes 117 cr
& Leftrightarrow x = frac{{left( {3 imes 33 imes 8 imes 117}
ight)}}{{left( {4 imes 13 imes 9}
ight)}} cr
& Leftrightarrow x = 198 cr} $$ ∴ Addition men to be employed = (198 - 117) = 81
9: D
Solution: Let the required number of persons be x Less days , More persons (Indirect proportion) More work , More persons (Direct proportion) [left. x08egin{gathered}
,{ ext{Days 2}}:4 hfill \
{ ext{Work 1}}:8 hfill \
end{gathered}
ight}::12:x] $$eqalign{
& herefore ,2 imes 1 imes x = 4 imes 8 imes 12 cr
& Leftrightarrow x = frac{{left( {4 imes 8 imes 12}
ight)}}{{left( 2
ight)}} cr
& Leftrightarrow x = 192 cr} $$
10: D
Solution: 5 cm on the map represents 1450 km ∴ 1 cm on the map represents $$left( {frac{{1450}}{5}}
ight)$$xa0 km = 290 km Hence, the scale is 1 cm : 290 km i.e., $$1:29 imes {10^6}{ ext{ }}$$ $$left[ {x08ecause 290{ ext{km}} = left( {29 imes {{10}^6}}
ight){ ext{cm}}}
ight]$$
11: B
Solution: Let the height of the building be x metres Lees lengthy shadow, Less is the height (Direct proportion) $$eqalign{
& herefore 40.25:28.75::17.5:x cr
& Leftrightarrow 40.25 imes x = 28.75 imes 17.5 cr
& Leftrightarrow x = frac{{left( {28.75 imes 17.5}
ight)}}{{40.25}} cr
& Leftrightarrow x = 12.5 cr} $$
12: B
Solution: Work done = $$frac{5}{8}$$ Balance work $$ = left( {1 - frac{5}{8}}
ight)$$ xa0 $$ = frac{3}{8}$$ Less work, Less days ( Direct proportion) Let the required number of days be x Then, $$eqalign{
& Leftrightarrow frac{5}{8}:frac{3}{8}::10:x cr
& Leftrightarrow frac{5}{8} imes x = frac{3}{8} imes 10 cr
& Leftrightarrow x = left( {frac{3}{8} imes 10 imes frac{8}{5}}
ight) cr
& Leftrightarrow x = 6 cr} $$
13: B
Solution: Let the required number of days be x Less men, More days (Indirect proportion) $$eqalign{
& herefore 42:56::24:x cr
& Leftrightarrow 42 imes x = 56 imes 24 cr
& Leftrightarrow x = left( {frac{{56 imes 24}}{{42}}}
ight) cr
& Leftrightarrow x = 32 cr} $$
14: B
Solution: Let the required number of men be x More days, Less men (Indirect proportion) $$eqalign{
& herefore { ext{ }}20:16::30:x cr
& Leftrightarrow 20x = 16 imes 30 cr
& Leftrightarrow x = left( {frac{{16 imes 30}}{{20}}}
ight) cr
& Leftrightarrow x = 24 cr} $$
15: D
Solution: Let the required number of mats be x More weavers , More mates ( Direct proportion ) More days, More mats ( Direct proportion ) [left. x08egin{gathered}
{ ext{Weavers }}4:8 hfill \
,,,,,,,,{ ext{Days }}4:8 hfill \
end{gathered}
ight}::4:x] $$eqalign{
& herefore 4 imes 4 imes x = 8 imes 8 imes 4 cr
& Leftrightarrow x = frac{{left( {8 imes 8 imes 4}
ight)}}{{left( {4 imes 4}
ight)}} cr
& Leftrightarrow x = 16 cr} $$
16: D
Solution: Since each maid would work with one mop, So,we shall consider 1 maid and 1 mop as 1 unit Let the required time be x hours Less maids and mops, More time (Indirect proportion) Less floor, Less time (Direct proportion) [left. x08egin{gathered}
{ ext{Maids & Mops 3}}:7 hfill \
,,,,,,,,,,,,,,,,,,,,,{ ext{Floors 7}}:3 hfill \
end{gathered}
ight}::7:x] $$eqalign{
& herefore { ext{ }}3 imes 7 imes x = 7 imes 3 imes 7 cr
& Leftrightarrow x = frac{{left( {7 imes 3 imes 7}
ight)}}{{left( {3 imes 7}
ight)}} cr
& Leftrightarrow x = 7 cr} $$
17: A
Solution: Since each gardener would work with one grass mower, So, we shall consider 1 gardener and 1 grass mower as one unit. Let the required time be x hours More gardeners and grass mowers, Less time (Indirect proportion) More area, More time (Direct proportion) [left. x08egin{gathered}
{ ext{Gardeners & grass mowers 8}}:4 hfill \
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,{ ext{Area 400}}:800 hfill \
end{gathered}
ight}::4:x] $$eqalign{
& herefore { ext{ }}8 imes 400 imes x = 4 imes 800 imes 4 cr
& Leftrightarrow x = frac{{left( {4 imes 800 imes 4}
ight)}}{{left( {8 imes 400}
ight)}} cr
& Leftrightarrow x = 4 cr} $$
18: A
Solution: Let the required number of bottles be x More machines, More bottles produced (Direct proportion) Less time, Less bottles produce (Direct proportion) [left. x08egin{gathered}
{ ext{Machines 6}}:15 hfill \
,,,,,,{ ext{Times 60}}:30 hfill \
end{gathered}
ight}::180:x] $$eqalign{
& herefore { ext{ }}6 imes 60 imes x = 15 imes 30 imes 180 cr
& Leftrightarrow x = frac{{left( {15 imes 30 imes 180}
ight)}}{{left( {6 imes 60}
ight)}} cr
& Leftrightarrow x = 225 cr} $$
19: B
Solution: Let the weekly earning be Rs. x More persons , More earning (Direct proportion) Less working hours, Less earning (Direct proportion) [left. x08egin{gathered}
,,,,,,,,,,,,,,,,{ ext{Persons 6}}:9 hfill \
{ ext{Working hours 8}}:6 hfill \
end{gathered}
ight}::8400:x] $$eqalign{
& herefore { ext{ }}6 imes 8 imes x = 9 imes 6 imes 8400 cr
& Leftrightarrow x = frac{{left( {9 imes 6 imes 8400}
ight)}}{{left( {6 imes 8}
ight)}} cr
& Leftrightarrow x = 9450 cr} $$
20: D
Solution: Let the required quantity be x kg. More workers, More quantity (Direct proportion) More days, More quantity (Direct proportion) [left. x08egin{gathered}
{ ext{Workers 5}}:8 hfill \
,,,,,,,,{ ext{Days 3}}:5 hfill \
end{gathered}
ight}::60:x] $$eqalign{
& herefore { ext{ }}5 imes 3 imes x = 8 imes 5 imes 60 cr
& Leftrightarrow x = frac{{left( {8 imes 5 imes 60}
ight)}}{{left( {5 imes 3}
ight)}} cr
& Leftrightarrow x = 160 cr} $$
21: N/A
Solution: Let the required number of days be x Less people, More days (Indirect proportion) Less quantity, Less days ( Direct proportion) [left. x08egin{gathered}
,,,,,,,{ ext{People 35}}:50 hfill \
{ ext{Quantity 350}}:50 hfill \
end{gathered}
ight}::30:x] $$eqalign{
& herefore { ext{ }}35 imes 350 imes x = 50 imes 50 imes 30 cr
& Leftrightarrow x = frac{{left( {50 imes 50 imes 30}
ight)}}{{left( {35 imes 350}
ight)}} cr
& Leftrightarrow x = frac{{300}}{{49}} cr
& Leftrightarrow x = 6frac{6}{{49}} cr} $$
22: B
Solution: Let the required number of days be x Less working hours, More days (Indirect Proportion) More men, Less days (Indirect Proportion) [left. x08egin{gathered}
{ ext{Working hours 4}}:8 hfill \
,,,,,,,,,,,,,,,,,,,,{ ext{Men 18}}:12 hfill \
end{gathered}
ight}::30:x] $$eqalign{
& herefore { ext{ }}4 imes 18 imes x = 8 imes 12 imes 30 cr
& Leftrightarrow x = frac{{left( {8 imes 12 imes 30}
ight)}}{{left( {4 imes 18}
ight)}} cr
& Leftrightarrow x = 40 cr} $$
23: C
Solution: Let the number of working hours per day be x More persons, Less working hours ( Indirect proportion) Less days, More working hours (Indirect proportion) [left. x08egin{gathered}
{ ext{Persons 7}}:5 hfill \
{ ext{Quantity 4}}:8 hfill \
end{gathered}
ight}::7:x] $$eqalign{
& herefore { ext{ }}7 imes 4 imes x = 5 imes 8 imes 7 cr
& Leftrightarrow x = frac{{left( {5 imes 8 imes 7}
ight)}}{{left( {7 imes 4}
ight)}} cr
& Leftrightarrow x = 10 cr} $$
24: B
Solution: Let the number of working hours per day be x More persons, Less working hours ( Indirect proportion) Less days, More working hours (Indirect proportion) [left. x08egin{gathered}
{ ext{Persons 7}}:4 hfill \
{ ext{Quantity 4}}:8 hfill \
end{gathered}
ight}::7:x] $$eqalign{
& herefore { ext{ }}7 imes 4 imes x = 4 imes 8 imes 7 cr
& Leftrightarrow x = frac{{left( {4 imes 8 imes 7}
ight)}}{{left( {7 imes 4}
ight)}} cr
& Leftrightarrow x = 8 cr} $$
25: D
Solution: Let the required number of working hours per day be x More pumps, Less working hours per day (Indirect proportion) Less days, More working hours per day (Indirect proportion) [left. x08egin{gathered}
{ ext{Pumps 4}}:3 hfill \
,,,,,,{ ext{Days 1}}:2 hfill \
end{gathered}
ight}::8:x] $$eqalign{
& herefore { ext{ }}4 imes 1 imes x = 3 imes 2 imes 8 cr
& Leftrightarrow x = frac{{left( {3 imes 2 imes 8}
ight)}}{{left( 4
ight)}} cr
& Leftrightarrow x = 12 cr} $$
26: D
Solution: Let the required earning be Rs. x 5 men = 7 women 7 men = $$ left( frac{7}{5} imes 7
ight) $$ xa0 women = $$frac{49}{5}$$ women ∴ (7 men and 13 women) $$eqalign{
& = left( {frac{{49}}{5} + 13}
ight){ ext{women}} cr
& = frac{{114}}{5}{ ext{ women}} cr} $$ Now, More women, More earning (Direct proportion) $$eqalign{
& herefore { ext{ }}7 : frac{{114}}{5}::{ ext{ 5}}250 : x cr
& Leftrightarrow 7x = left( {frac{{114}}{5} imes 5250}
ight) cr
& Leftrightarrow 7x = 119700 cr
& Leftrightarrow x = 17100 cr} $$
27: B
Solution: Let the required number of days be x 3 men = 6 women ⇒12 men = (2 × 12) women = 24 women ∴ 12 men and 8 women = (24 + 8) women = 32 women Now, More women, Less days (Indirect Proportion) $$eqalign{
& herefore { ext{ }}32:6::20:x cr
& Leftrightarrow x = left( {frac{{6 imes 20}}{{32}}}
ight) cr
& Leftrightarrow x = frac{{15}}{4} cr
& Leftrightarrow x = 3frac{3}{4} cr} $$
28: C
Solution: Let the required number of days be x Then, More pumps, Less days (Indirect proportion) Less working hour/day, More days (Indirect proportion) [left. x08egin{gathered}
,,,,,,,,,,,,,,,,,,,,,,{ ext{Pumps 196}}:49 hfill \
{ ext{Working hour/day 5}}:8 hfill \
end{gathered}
ight}::frac{{13}}{2}:x] $$eqalign{
& herefore { ext{ }}196 imes 5 imes x = 49 imes 8 imes frac{{13}}{2} cr
& Leftrightarrow x = left( {49 imes 8 imes frac{{13}}{2} imes frac{1}{{196 imes 5}}}
ight) cr
& Leftrightarrow x = frac{{13}}{5} cr
& Leftrightarrow x = 2frac{3}{5} cr} $$
29: B
Solution: Let the required number of labourers be x Less working hour/day, More labours (Indirect proportion) More days, Less labourers (Indirect proportion) [left. x08egin{gathered}
{ ext{Working hours/day 6}}:7 hfill \
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,{ ext{Days 30}}:18 hfill \
end{gathered}
ight}::30:x] $$eqalign{
& herefore 6 imes 30 imes x = 7 imes 18 imes 30 cr
& Leftrightarrow 6x = 126 cr
& Leftrightarrow x = 21 cr} $$
30: D
Solution: Let the required number of working hours per day be x. More pumps, Less working hours per day (Indirect Proportion) Less days, More working hours per day (Indirect Proportion) [left. x08egin{gathered}
{ ext{Pumps 4}}:3 hfill \
{ ext{Days}},,,,,,,,{ ext{1}}:2 hfill \
end{gathered}
ight}::8:x] $$eqalign{
& herefore 4 imes 1 imes x = 3 imes 2 imes 8 cr
& Rightarrow x = frac{{ {3 imes 2 imes 8} }}{{ 4 }} cr
& Rightarrow x = 12 cr} $$
31: D
Solution: $$eqalign{
& { ext{Cost of }}x{ ext{ metres}} cr
& = { ext{Rs}}{ ext{. }}d cr
& { ext{Coast of 1 metre}} cr
& = { ext{Rs}}{ ext{.}}left( {frac{d}{x}}
ight) cr
& { ext{Cost of }}y{ ext{ metres}} cr
& = { ext{Rs}}{ ext{.}}left( {frac{d}{x} imes y}
ight) cr
& = { ext{Rs}}{ ext{.}} {frac{{yd}}{x}} cr} $$
32: B
Solution: Let the required number of bottles be x . More machines, More bottles (Direct Proportion) More minutes, More bottles (Direct Proportion) [left. x08egin{gathered}
{ ext{Machines}},,,,,,,,,,,,,,,,{ ext{6}}:10 hfill \
{ ext{Time(in min}}{ ext{.)}},,{ ext{1}}:4 hfill \
end{gathered}
ight}::270:x] $$eqalign{
& herefore 6 imes 1 imes x = 10 imes 4 imes 270 cr
& Rightarrow x = frac{{ {10 imes 4 imes 270} }}{{ 6 }} cr
& Rightarrow x = 1800 cr} $$
33: C
Solution: After 10 days : 150 men had food for 35 days. Suppose 125 men had food for x days. Now, Less men, More days (Indirect Proportion) $$eqalign{
& herefore 125:150::35:x cr
& Rightarrow 125 imes x = 150 imes 35 cr
& Rightarrow x = frac{{150 imes 35}}{{125}} cr
& Rightarrow x = 42 cr} $$
34: B
Solution: Let the required number of days bex. Less persons, More days (Indirect Proportion) More working hours per day, Less days (Indirect Proportion) [left. x08egin{gathered}
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,{ ext{Persons }},30:39 hfill \
{ ext{Working hour/day }},{ ext{6}}:{ ext{5}} hfill \
end{gathered}
ight}::12:x] $$eqalign{
& herefore 30 imes 6 imes x = 39 imes 5 imes 12 cr
& Rightarrow x = frac{{ {39 imes 5 imes 12} }}{{ {30 imes 6} }} cr
& Rightarrow x = 13 cr} $$
35: B
Solution: $$eqalign{
& { ext{Work}},{ ext{done}} = frac{5}{8} cr
& { ext{Balance}},{ ext{work}} = {1 - frac{5}{8}} = frac{3}{8} cr
& { ext{Let}},{ ext{the}},{ ext{required}},{ ext{number}},{ ext{of}},{ ext{days}},{ ext{be}},x cr
& { ext{Then}}, cr
&frac{5}{8}:frac{3}{8} :: 10:x cr
& Rightarrow frac{5}{8} imes x = frac{3}{8} imes 10 cr
& Rightarrow x = {frac{3}{8} imes 10 imes frac{8}{5}} cr
& Rightarrow x = 6 cr} $$
36: A
Solution: $$eqalign{
& { ext{Let}},{ ext{the}},{ ext{required}},{ ext{weight}},{ ext{be}},x,{ ext{kg}}. cr
& { ext{Less}},{ ext{weight,}},{ ext{less}},{ ext{cost}},left( {{ ext{Direct}},{ ext{Proportion}}}
ight) cr
& herefore 250:200::60:x cr
& Rightarrow 250 imes x = {200 imes 60} cr
& Rightarrow x = frac{{ {200 imes 60} }}{{250}} cr
& Rightarrow x = 48 cr} $$
37: C
Solution: Let the required number of days be x. Less cows, More days (Indirect Proportion) Less bags, Less days (Direct Proportion) [left. x08egin{gathered}
{ ext{Cows}},,,,,1:40 hfill \
{ ext{Bags}},,,,,40:1 hfill \
end{gathered}
ight}::40:x] $$eqalign{
& herefore 1 imes 40 imes x = 40 imes 1 imes 40 cr
& Rightarrow x = 40 cr} $$
38: B
Solution: Let the required number of revolutions made by larger wheel be x . Then, More cogs, Less revolutions (Indirect Proportion) $$eqalign{
& herefore 14:6::21:x cr
& Rightarrow 14 imes x = 6 imes 21 cr
& Rightarrow x = frac{{6 imes 21}}{{14}} cr
& Rightarrow x = 9 cr} $$
39: C
Solution: Let the required number days be x. Less spiders, More days (Indirect Proportion) Less webs, Less days (Direct Proportion) [left. x08egin{gathered}
{ ext{Spiders}},,,,,1:7 hfill \
,,,{ ext{Webs}},,,,,7:1 hfill \
end{gathered}
ight}::7:x] $$eqalign{
& herefore 1 imes 7 imes x = 7 imes 1 imes 7 cr
& Rightarrow x = 7 cr} $$
40: B
Solution: Let the height of the building x metres. Less lengthy shadow, Less in the height (Direct Proportion) $$eqalign{
& herefore 40.25:28.75::17.5:x cr
& Rightarrow 40.25 imes x = 28.75 imes 17.5 cr
& Rightarrow x = frac{{28.75 imes 17.5}}{{40.25}} cr
& Rightarrow x = 12.5 cr} $$
41: B
Solution: There is a meal for 200 children 150 children have taken the meal Remaining meal is to be catered to 50 children Now, 200 children = 120 men ∴ 50 children $$eqalign{
& = left( {frac{{120}}{{200}} imes 50}
ight){ ext{men}} cr
& = { ext{30 men}} cr} $$
42: B
Solution: Le the required time be x seconds. More metres, More time (Direct Proportion) $$eqalign{
& herefore 0.128:25::1:x cr
& Rightarrow 0.128x = 25 imes 1 cr
& x = frac{{25}}{{0.128}} = frac{{25 imes 1000}}{{128}} cr
& Rightarrow x = 195.31 cr} $$ ∴ Required time = 195 sec (approximately)
43: D
Solution: Let the required number of days be x . Less men, More days (Indirect Proportion) $$eqalign{
& herefore 27:36::18:x cr
& Rightarrow 27 imes x = 36 imes 18 cr
& Rightarrow x = frac{{36 imes 18}}{{27}} cr
& Rightarrow x = 24 cr} $$
44: D
Solution: Let the required number of bottles be x. More weavers, More mats (Direct Proportion) More days, More mats (Direct Proportion) [left. x08egin{gathered}
{ ext{Wavers}},,,,4:8 hfill \
,,,,,,{ ext{Days}},,,,4:8 hfill \
end{gathered}
ight}::4:x] $$eqalign{
& herefore 4 imes 4 imes x = 8 imes 8 imes 4 cr
& Rightarrow x = frac{{ {8 imes 8 imes 4} }}{{4 imes 4}} cr
& Rightarrow x = 16 cr} $$
45: D
Solution: Let the required price be Rs. x More mangoes, More price (Direct proportion) $$eqalign{
& herefore 357:left( {49 imes 12}
ight)::1517.25:x cr
& Leftrightarrow 357x = left( {49 imes 12 imes 1517.25}
ight) cr
& Leftrightarrow x = frac{{left( {49 imes 12 imes 1517.25}
ight)}}{{357}} cr
& Leftrightarrow x = 2499 cr} $$ Hence, the approximate price is Rs. 2500
46: B
Solution: Let the required time be x seconds Then, More metres, More time (direct proportion) $$eqalign{
& herefore 0.128:25::1:x cr
& Leftrightarrow x = frac{{25}}{{0.128}} cr
& Leftrightarrow x = frac{{25 imes 1000}}{{128}} cr
& Leftrightarrow x = 195.31 cr} $$` ∴ Required time =195 seconds (approx)
47: C
Solution: Let the dimension of the shorter side be x More is the longer side, More is the shorter side (Direct proportion) $$eqalign{
& herefore 2frac{1}{2}:4::1frac{7}{8}:x cr
& Leftrightarrow frac{5}{2}x = 4 imes frac{{15}}{8} cr
& Leftrightarrow x = left( {frac{{15}}{2} imes frac{2}{5}}
ight) cr
& Leftrightarrow x = 3 cr} $$
48: A
Solution: Total number of days = (30 + 31 + 30) = 91 Let the number of bananas be x More days, More bananas (Direct proportion) $$eqalign{
& herefore 7:91::651:x cr
& Rightarrow 7x = 91 imes 651 cr
& Rightarrow x = left( {frac{{91 imes 651}}{7}}
ight) cr
& Rightarrow x = 8463 cr} $$
49: C
Solution: Remaining part $$eqalign{
& = left( {1 - frac{4}{9}}
ight) cr
& = frac{5}{9}{ ext{ }} cr} $$ Let the required time be x minutes More volume to be filled , More time taken (Direct proportion) $$eqalign{
& herefore { ext{ }}frac{4}{9}:frac{5}{9}::1:x cr
& Rightarrow frac{4}{9}x = frac{5}{9} cr
& Rightarrow x = left( {frac{5}{9} imes frac{9}{4}}
ight) cr
& Rightarrow x = frac{5}{4}{ ext{ }} cr} $$
50: B
Solution: Let the required quantity of coal be x metric tonnes More engines, More coal (Direct proportion) More hours per day, More coal (Direct proportion) More rate, More coal (Direct proportion) [left. x08egin{gathered}
,,,,,,,,,,,,,,{ ext{Engines 5}}:8 hfill \
{ ext{Hours per day 9}}:10 hfill \
,,,,,,,,,,,,,,,,,,,,{ ext{Rate }}frac{1}{3}:frac{1}{4} hfill \
end{gathered}
ight}::6:x] $$eqalign{
& herefore ,,left( {5 imes 9 imes frac{1}{3} imes x}
ight) = left( {8 imes 10 imes frac{1}{4} imes 6}
ight) cr
& Leftrightarrow 15x = 120 cr
& Leftrightarrow x = 8 cr} $$
51: C
Solution: Let the required number of days be x 2 men of latter type = 3 men of former type 12 men of latter type = $$left( {frac{3}{2} imes 12}
ight)$$ = 18 men of former type More men, Less days (Indirect proportion) Less working hours, More days (Indirect proportion) [left. x08egin{gathered}
,,,,,,,,,,,,,,,,{ ext{Men 18}}:9 hfill \
{ ext{Working hrs 6}}:frac{{15}}{2} hfill \
end{gathered}
ight}::20:x] $$eqalign{
& herefore ,18 imes 6 imes x = 9 imes frac{{15}}{2} imes 20 cr
& Leftrightarrow 108x = 1350 cr
& Leftrightarrow x = frac{{25}}{2} cr
& Leftrightarrow x = 12frac{1}{2} cr} $$
52: D
Solution: 3 women ≡ 2 men So, 21 women ≡ 14 men Less men, More days (Indirect proportion) Less hours per day, More days (Indirect proportion) [left. x08egin{gathered}
,,,,,,,,,,,,,,,,{ ext{Men 14}}:15 hfill \
{ ext{Hours per day 6}}:8 hfill \
end{gathered}
ight}::21:x] $$eqalign{
& herefore ,left( {14 imes 6 imes x}
ight) = left( {15 imes 8 imes 21}
ight) cr
& Leftrightarrow x = frac{{left( {15 imes 8 imes 21}
ight)}}{{left( {14 imes 6}
ight)}} cr
& Leftrightarrow x = 30 cr} $$ ∴ Required number of days = 30
53: B
Solution: Let the remaining food last for x days 4000 soldiers had provision for 160 days 3200 soldiers had provision for x days Less men, More days (Indirect proportion) $$eqalign{
& herefore ,3200:4000::160:x cr
& Leftrightarrow 3200x = 4000 imes 160 cr
& Leftrightarrow x = frac{{left( {4000 imes 160}
ight)}}{{3200}} cr
& Leftrightarrow x = 200 cr} $$
54: A
Solution: Let the remaining food last for x days 500 men had provision for = (27 - 3) = 24 days (500 + 300) men had provision for x days More men, Less days (Indirect proportion) $$eqalign{
& herefore ,800:500::24:x cr
& Leftrightarrow left( {800 imes x}
ight) = left( {500 imes 24}
ight) cr
& Leftrightarrow x = frac{{left( {500 imes 24}
ight)}}{{800}} cr
& Leftrightarrow x = 15 cr} $$
55: D
Solution: Initially, Let there be x men having food for y days After 10 days, x men had food for days (y - 10) Also, $$left( {x - frac{x}{5}}
ight)$$ xa0 men had food for y days $$eqalign{
& herefore ,xleft( {y - 10}
ight) = frac{{4x}}{5} imes y cr
& Leftrightarrow 5xy - 50x = 4xy cr
& Leftrightarrow xy - 50x = 0 cr
& Leftrightarrow xleft( {y - 50}
ight) = 0 cr
& Leftrightarrow y - 50 = 0 cr
& Leftrightarrow y = 50 cr} $$
56: C
Solution: Let there be x men originally So, x men had provisions 40 days whereas (x + 500) men consumed it in 35 days More men, Less days (Indirect proportion) $$eqalign{
& herefore ,left( {x + 500}
ight):x::40:35 cr
& Leftrightarrow 35 imes left( {x + 500}
ight) = 40x cr
& Leftrightarrow 5x = 35 imes 500 cr
& Leftrightarrow x = left( {frac{{35 imes 500}}{5}}
ight) cr
& Leftrightarrow x = 3500 cr} $$
57: C
Solution: Let the team take x days to finish 360 pieces Then, number of pieces made each day =
$$frac{{360}}{x}$$ More number of pieces per day, Less days (Indirect proportion) $$eqalign{
& herefore ,left( {frac{{360}}{x} + 4}
ight):frac{{360}}{x}::x:left( {x - 1}
ight) cr
& Leftrightarrow left( {frac{{360}}{x} + 4}
ight) left( {x - 1}
ight) = frac{{360}}{x} imes x cr
& Leftrightarrow 360 - frac{{360}}{x} + 4x - 4 = 360 cr
& Leftrightarrow 4x - frac{{360}}{x} - 4 = 0 cr
& Leftrightarrow x - frac{{90}}{x} - 1 = 0 cr
& Leftrightarrow {x^2} - x - 90 = 0 cr
& Leftrightarrow left( {x - 10}
ight)left( {x + 9}
ight) = 0 cr
& Leftrightarrow x = 10 cr} $$
58: A
Solution: Ratio of time taken by a woman, a man and a boy $$eqalign{
& = 8:6:12 cr
& = 4:3:6 cr} $$ So, 4 women ≡ 3 men ≡ 6 boy (12 mens + 12 womens + 12 boys) $$eqalign{
& = left[ {12 + left( {frac{3}{4} imes 12}
ight) + left( {frac{3}{6} imes 12}
ight)}
ight]{ ext{men}} cr
& { ext{ = }}left( {12 + 9 + 6}
ight){ ext{men}} cr
& = 27{ ext{ men}} cr} $$ Let the required number of days be x More men, Less days (Indirect proportion) More working hours, Less days (Indirect proportion) [left. x08egin{gathered}
{ ext{Working hours 8}}:6 hfill \
,,,,,,,,,,,,,,,,,,,,,{ ext{Men 27}}:9 hfill \
end{gathered}
ight}::6:x] $$eqalign{
& herefore ,27 imes 8 imes x = 9 imes 6 imes 6 cr
& Leftrightarrow x = frac{{left( {9 imes 6 imes 6}
ight)}}{{left( {27 imes 8}
ight)}} cr
& Leftrightarrow x = frac{3}{2} cr
& Leftrightarrow x = 1frac{1}{2} cr} $$
59: B
Solution: 1 man ≡ 2 boys ⇔ (12 men + 18 boys) ≡ (12 × 2 ×18) boys = 42 boys Let required number of boys = x ⇒ (21 men + x boys) ≡ (21 × 2 × x) boys = (42 + x) boys Less days, More boys (Indirect proportion) More hours per day, Less boys (Indirect proportion) More work, More boys (Direct proportion) [left. x08egin{gathered}
,,,,,,,,,,,,,,,,{ ext{Days 50}}:60 hfill \
{ ext{Hours per day 9}}:frac{{15}}{2} hfill \
,,,,,,,,,,,,,,,,,,,,,{ ext{Work }}1:2 hfill \
end{gathered}
ight}::42:left( {42 + x}
ight)] $$ herefore left[ {50 imes 9 imes 1 imes left( {42 + x}
ight)}
ight] = $$ xa0 xa0 $$left( {60 imes frac{{15}}{2} imes 2 imes 42}
ight)$$ $$eqalign{
& Leftrightarrow left( {42 + x}
ight) = frac{{37800}}{{450}} cr
& Leftrightarrow 42 + x = 84 cr
& Leftrightarrow x = 42 cr} $$
60: B
Solution: Cloth is required for 1 shirt = 2 m, 60 cm or 260 cm Cloth is required for 7 shirt = 260 × 7 = 1820 cm or 18 m 20 cm
61: C
Solution: 1 score of papers = 20 papers Cost of 4 dozen papers = Rs.24 Cost of 20 papers $$eqalign{
& = frac{{24}}{{4 imes 12}} imes 20 cr
& = { ext{Rs}}{ ext{.10}} cr} $$
62: B
Solution: Cost of 8 fan's and 14 oven's is Rs. 36520 Cost of 4 fan's and 7 oven's is Rs. $$frac{{{ ext{36520}}}}{2}$$xa0 = Rs.18260 Cost of 12 fan's and 21 oven's is = 18260 × 3 = Rs. 54780
63: B
Solution: Cost of 5 kgs apples Rs. 450 Cost of 1 kg apples Rs. $$frac{{{ ext{450}}}}{5}$$ Cost of 8 kgs apples = $$frac{{450}}{5} imes 8$$ xa0 = Rs.720 Cost of 12 dozens mangoes Rs. 4320 Cost of 1 dozen mangoes Rs. $$frac{{{ ext{4320}}}}{{12}}$$ Cost of 8 dozen mangoes = $$frac{{4320}}{{12}} imes 8$$ xa0 = Rs. 2880 Cost of 4 kgs oranges = Rs. 240 Cost of 1 kg orange = Rs. $$frac{{{ ext{240}}}}{4}$$ Cost of 8 kgs oranges = $$frac{{240}}{4} imes 8$$ xa0 = Rs. 480 Total cost = 720 + 2880 + 480 = Rs. 4080
64: C
Solution: Cost of 21 pencils and 9 clippers = Rs. 819 Cost of 7 pencils and 3 clippers = $$frac{{819}}{3}$$ = Rs. 273
65: B
Solution: Let, L = large ships, M = medium ships, S = small ships Now from the question, 4L ≡ 7S $$eqalign{
& { ext{15L}} = left( {frac{7}{4} imes 15}
ight){ ext{S}} = frac{{105}}{4}{ ext{S}} cr
& { ext{Also, 2L}} = left( {frac{7}{4} imes 2}
ight){ ext{S}} = frac{7}{2}{ ext{S}} cr
& { ext{3M}} equiv 2{ ext{L}} + { ext{1S }} equiv left( {frac{7}{2} + 1}
ight){ ext{S}} = frac{9}{2}{ ext{S}} cr
& Leftrightarrow { ext{ 7M}} = left( {frac{9}{2} imes frac{1}{3} imes 7}
ight),,{ ext{S}} = frac{{21}}{2}{ ext{S}} cr
& herefore ,left( {{ ext{15L}} + { ext{7M}} + { ext{14S}}}
ight){ ext{ ships}} cr
& equiv left( {frac{{105}}{4} + frac{{21}}{2} + 14}
ight){ ext{S}} cr
& = frac{{203}}{4}{ ext{S}} cr
& left( {{ ext{12 large}} + 14{ ext{ medium}} + 2{ ext{1 small}}}
ight){ ext{ ships}} cr
& equiv left[ {left( {frac{7}{4} imes 12}
ight) + left( {frac{{21}}{2} imes 2}
ight) + 21}
ight]{ ext{S}} cr
& = left( {21 + 21 + 21}
ight){ ext{S}} cr
& = 63,{ ext{S}} cr} $$ Let the required number of journeys be x More ships, Less journeys (Indirect proportion) $$eqalign{
& herefore ,63:frac{{203}}{4}::36:x cr
& Leftrightarrow 63x = frac{{203}}{4} imes 36 = 1827 cr
& Leftrightarrow x = frac{{1827}}{{63}} cr
& Leftrightarrow x = 29 cr} $$ Alternate: Now from the question, $$eqalign{
& 4L = 7S cr
& Rightarrow frac{L}{S} = frac{7}{4} cr
& Rightarrow L = 7x

S = 4x cr
& 3M = 2L + S cr
& Rightarrow M = frac{{2 imes 7x + 4x}}{3} cr
& Rightarrow M = 6x cr} $$ Thus, ratio of large, medium and small = 7 : 6 : 4 So, numbers of journeys: $$eqalign{
& = frac{{(15 imes 7 + 7 imes 6 + 14 imes 4)36}}{{12 imes 7 + 14 imes 6 + 21 imes 4}} cr
& = frac{{7308}}{{252}} cr
& = 29 cr} $$
66: B
Solution: Let the total number of men to be engaged be $$x$$ More length, More labourers (Direct proportion) Less days, More labourers (Indirect proportion) [left. x08egin{gathered}
,,,,,,,,,,,,{ ext{Lentgh 26}}:39 hfill \
,,,,,,,,,,,,,,,,,,,{ ext{Days 6}}:18 hfill \
{ ext{Hours per day }}9:8 hfill \
end{gathered}
ight}::17:x] $$eqalign{
& herefore { ext{ }}26 imes 6 imes 9 imes x = 39 imes 18 imes 8 imes 17 cr
& Leftrightarrow x = frac{{left( {39 imes 18 imes 8 imes 17}
ight)}}{{left( {26 imes 6 imes 9}
ight)}} cr
& Leftrightarrow x = 68 cr} $$ ∴ Number of more labourers = (68 -17) = 51